(B) The given reaction is an example of a pseudo-first-order reaction.In this reaction,water is present in large excess,so its concentration remains e

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$\text{Rate} = K [\text{sucrose}] [\text{water}]^0$

(B) The given reaction is an example of a pseudo-first-order reaction.In this reaction,water is present in large excess,so its concentration remains effectively constant throughout the reaction.Therefore,the rate of the reaction depends only on the concentration of sucrose.The rate law is expressed as $\text{Rate} = K [\text{sucrose}]^1 [\text{water}]^0$,which simplifies to $\text{Rate} = K [\text{sucrose}]$.Thus,option $B$ is correct.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

Easy

The rate law for the reaction $\text{Sucrose} + \text{Water} \xrightarrow{H^+} \text{Glucose} + \text{Fructose}$ is given by:

A
$\text{Rate} = K [\text{sucrose}] [\text{water}]$
B
$\text{Rate} = K [\text{sucrose}] [\text{water}]^0$
C
$\text{Rate} = K [\text{sucrose}]^0 [\text{water}]$
D
$\text{Rate} = K [\text{sucrose}]^{1/2} [\text{water}]^{1/2}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

Rate law , Rate constant , Order of Reaction and Molecularity

For a reaction,$A + B \rightarrow$ products,the rate of the reaction at various concentrations is given below. The rate law for the above reaction is:
Expt. no. $[A]$ $[B]$ Rate $(\text{mol} \ \text{dm}^{-3} \ \text{s}^{-1})$
$1$ $0.2$ $0.2$ $2$
$2$ $0.2$ $0.4$ $4$
$3$ $0.6$ $0.4$ $36$

Expt. no.	$[A]$	$[B]$	Rate $(\text{mol} \ \text{dm}^{-3} \ \text{s}^{-1})$
$1$	$0.2$	$0.2$	$2$
$2$	$0.2$	$0.4$	$4$
$3$	$0.6$	$0.4$	$36$

EasyKCET 2012

View Solution

In the reaction $A + B \to \text{Products}$,if $B$ is taken in excess,then it is an example of

Easy

View Solution

For a certain reaction,the rate constant $K = 2.37 \times 10^2 \ L^2 \ mol^{-2} \ s^{-1}$. What is the order of the reaction?

EasyGSEB 2024

View Solution

The given data are for the reaction:
$2NO_{(g)} + Cl_{2(g)} \to 2NOCl_{(g)}$ at $298 \ K$
Experiment $[Cl_2] \ (M)$ $[NO] \ (M)$ Rate $(mol \ L^{-1} \sec^{-1})$
$I$ $0.05$ $0.05$ $1 \times 10^{-3}$
$II$ $0.15$ $0.05$ $3 \times 10^{-3}$
$III$ $0.05$ $0.15$ $9 \times 10^{-3}$

The rate law for the reaction is:

Medium

View Solution

Differential form of the rate equation is $\frac{dx}{dt} = k[P][Q]^{0.5}[R]^{0.5}$. Which statement about the above equation is wrong?

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Experiment	$[Cl_2] \ (M)$	$[NO] \ (M)$	Rate $(mol \ L^{-1} \sec^{-1})$
$I$	$0.05$	$0.05$	$1 \times 10^{-3}$
$II$	$0.15$	$0.05$	$3 \times 10^{-3}$
$III$	$0.05$	$0.15$	$9 \times 10^{-3}$

The rate law for the reaction $\text{Sucrose} + \text{Water} \xrightarrow{H^+} \text{Glucose} + \text{Fructose}$ is given by:

Similar Questions

For a reaction,$A + B \rightarrow$ products,the rate of the reaction at various concentrations is given below. The rate law for the above reaction is:Expt. no.$[A]$$[B]$Rate $(\text{mol} \ \text{dm}^{-3} \ \text{s}^{-1})$$1$$0.2$$0.2$$2$$2$$0.2$$0.4$$4$$3$$0.6$$0.4$$36$

In the reaction $A + B \to \text{Products}$,if $B$ is taken in excess,then it is an example of

For a certain reaction,the rate constant $K = 2.37 \times 10^2 \ L^2 \ mol^{-2} \ s^{-1}$. What is the order of the reaction?

The given data are for the reaction:$2NO_{(g)} + Cl_{2(g)} \to 2NOCl_{(g)}$ at $298 \ K$Experiment$[Cl_2] \ (M)$$[NO] \ (M)$Rate $(mol \ L^{-1} \sec^{-1})$$I$$0.05$$0.05$$1 \times 10^{-3}$$II$$0.15$$0.05$$3 \times 10^{-3}$$III$$0.05$$0.15$$9 \times 10^{-3}$The rate law for the reaction is:

Differential form of the rate equation is $\frac{dx}{dt} = k[P][Q]^{0.5}[R]^{0.5}$. Which statement about the above equation is wrong?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

For a reaction,$A + B \rightarrow$ products,the rate of the reaction at various concentrations is given below. The rate law for the above reaction is:
Expt. no. $[A]$ $[B]$ Rate $(\text{mol} \ \text{dm}^{-3} \ \text{s}^{-1})$
$1$ $0.2$ $0.2$ $2$
$2$ $0.2$ $0.4$ $4$
$3$ $0.6$ $0.4$ $36$